Find the area of parallelogram ABCD given m A = 30 and the following measures. AB = 6 ft.; AX = 3√3 A = ? A. 18 ft.² B. 18√3 ft.² C. 36√3 ft.²

Accepted Solution

Answer:Given that a parallelogram ABCD has sides AB= 6 ft and AX = 3√3Angle A =30To find the area of the parallelogramWe have area of parallelogram = base x heightHere base can be taken as side AB = 6 ftHeight = perpendicular distance of AB from vertex X= AX sin A= 3√3sin30=1.5√3Hence area =6(1.5√3)=9√3ft^2Read more on Brainly.com - explanation: